Posted by **Samantha** on Saturday, August 8, 2009 at 7:34pm.

A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 450 seconds and a standard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 335 seconds.

Is the answer 0.0107? Anyone please

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**J.J.**, Saturday, August 8, 2009 at 9:25pm
can some one please help me!!!

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**Marth**, Saturday, August 8, 2009 at 9:38pm
You are given the normal model N(450, 50)

Find the z score for 335 seconds.

z = (x-u)/s

where u = mu and s = sigma.

z = (335-450)/50

z = -2.3

Now use the normal cumulative distribution function on a calculator or program to find the P(z<-2.3)

normalCDF(-99,-2.3) = .0107

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**Maria**, Sunday, August 9, 2009 at 8:20pm
Marth this are my choices

A) 0.9893

B) 0.0107

C) 0.4893

D) 0.5107

So I'm assuming it's letter B? correct

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**Arturo**, Sunday, March 29, 2015 at 2:09pm
Dahhhh lol

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