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December 20, 2014

December 20, 2014

Posted by **Monique** on Saturday, August 8, 2009 at 7:29pm.

f(x) = -(x+3)^2, x is greater than or equal to 3

I know the first thing you do is switch the variables, so it looks like this:

x = -(y+3)^2

Then expand:

x = -y^2-6y-9

And solve for y:

x + 9 = -y^2-6y

I get a little confused after that with y. Help please? Thank you very much!

- Math (repost) -
**Marth**, Saturday, August 8, 2009 at 9:40pmAt the step where you have x = -(y+3)^2, you should take the square root of both sides.

sqrt(x) = -(y+3)

-sqrt(x) = y+3

-sqrt(x) - 3 = y

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