Friday

April 18, 2014

April 18, 2014

Posted by **Anonymous** on Friday, August 7, 2009 at 10:16pm.

What is the speed of passenger train? ____mph

What is the speed of freight train? _______ Mph

10) A long distance trucker travels 88 miles in one direction during a snowstorm. The return trip in rainy weather was accomplished at double the speed and took 2 hours less time. Find the speed going

The speed going was ____ mph.

- MATH Algebra -
**DrBob222**, Friday, August 7, 2009 at 10:29pmP = speed of passenger train.

F = speed of freight train.

================

P+6 = F

distance = rate x time or rearrange to

time = d/r

For P train time = 280/P

For F frain time = 250/F

The times are equal so

280/P = 250/F but you know P = F + 6 so substitute F + 6 for P to obtain

280/(F+6) = 250/F

solve for F.

- MATH Algebra -
**DrBob222**, Friday, August 7, 2009 at 10:44pmSpeed forward direction = F

Speed return trip = R

====================

R = 2F

The time it takes for forward is

t = d/r = 88/F

The time for return is

t = d/r = 88/R or 88/2F

IF the times were equal (they aren't) then

88/F = 88/2F BUT it takes the return trip 2 hours less; therefore, we must add 2 hours to the return trip to make the times equal.

88/F = (88/2F) + 2

solve for F, the speed in the forward direction.

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