Tuesday

September 16, 2014

September 16, 2014

Posted by **B.B.** on Friday, August 7, 2009 at 3:41pm.

A bag contains seven blue marbles and five red marbles. One marble is drawn at random without replacement, and then a second marble is drawn. What is the probability that the second marble is blue if the first marble was blue?

I say 6/11, is this right?

Thanks.

- Math -
**drwls**, Friday, August 7, 2009 at 3:58pmIf the first drawn marble was blue, there are 6 blues and 5 reds left. Yes, the answer is 6/11.

**Answer this Question**

**Related Questions**

math - 1.A box contains four red marbles, seven white marbles, and five blue ...

math214 - A box contains four red marbles, seven white marbles and five blue ...

Math - Can someone please explain how to solve this problem? A bag contains 6 ...

Algebra 2 - A bag contains five red marbles and three blue marbles. In how many ...

prealgebra - a bag contains 6 red marbles, 5 yellow marbles, 7 blue marbles, and...

algebra 2 - The bag contains three red marbles, two blue marbles, and seven ...

Math - A bag contains 4 green marbles, 6 red marbles, and 2 white marbles. Three...

math - A bag contains 7 blue marbles, 5 red marbles, and 9 green marbles. A ...

Math - A bag contains nine red marbles, four green marbles, three blue marbles, ...

math - the bag contains 20 red marbles and30 white marbles and 40 blue ones what...