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algebra 2

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i have a piece of wood 72 inches long i cut it into 3 peices. the 2nd peice is 6 inches longer than the 1st the third id 6 inches longer than the 2nd. write and equation and solve??

  • algebra 2 - ,

    First you define the variable,
    let x be the length of the first piece in inches.
    Then make an equation using the variable to represent the given relations:
    x + (x+6) + (x+6)+6 = 72
    Collect like terms:
    3x + 18 = 72
    Solve for x:
    3x = 72 - 18 = 54
    x = 18
    Finally, verify the answer using the given relations.
    First piece = 18 inches
    second piece = 24 inches
    third piece = 30 inches
    Total = 18+24+30 = 72 inches
    The solution is correct.

  • algebra 2 - ,

    thank you

  • algebra 2 - ,

    Frist .18inches, 2nd .18+6=24inches,3rd. 24+6=30inches.
    To check. 18 +24+ 30=72

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