Posted by **bandit** on Thursday, August 6, 2009 at 10:26pm.

i have a piece of wood 72 inches long i cut it into 3 peices. the 2nd peice is 6 inches longer than the 1st the third id 6 inches longer than the 2nd. write and equation and solve??

- algebra 2 -
**MathMate**, Thursday, August 6, 2009 at 10:31pm
First you define the variable,

let x be the length of the first piece in inches.

Then make an equation using the variable to represent the given relations:

x + (x+6) + (x+6)+6 = 72

Collect like terms:

3x + 18 = 72

Solve for x:

3x = 72 - 18 = 54

x = 18

Finally, verify the answer using the given relations.

First piece = 18 inches

second piece = 24 inches

third piece = 30 inches

Total = 18+24+30 = 72 inches

The solution is correct.

- algebra 2 -
**bandit**, Thursday, August 6, 2009 at 11:19pm
thank you

- algebra 2 -
**Pj**, Sunday, September 20, 2015 at 3:20am
Frist .18inches, 2nd .18+6=24inches,3rd. 24+6=30inches.

To check. 18 +24+ 30=72

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