A -3.5uC charge experiences a 13 ihat-N electric force in a certain electric field.What force would a proton experience in the same field?
I got -7.28*10^-18
from (1.6*10^-19)(-45.5)
I got -45.5 from multiplying 13 by -3.5
What am I doing wrong?
ok both ways were wrong, you use cross multiplication: 1.6E-19/F x -3.5E-6/13N
F(on proton)= (13N *1.6E-19)/ -3.5E-6
I would have just done a proportion:
Force= 13N*(-3.5E-6/1.6E-19)= I don't get your answer.
I got -2.84E14 plugged it in and got the wrong answer
change the proportion to
13N(1.6E-19/3.5E-6)
check that thinking.
To find the force experienced by a proton in the same electric field, you are using the equation:
Force = charge * electric field
For the proton, the charge is +1.6 x 10^-19 C, and the electric field remains the same at -45.5 N ihat.
However, the mistake lies in how you arrived at the value of -45.5 N. multiplying 13 by -3.5 would give you -45.5, but the unit would be N·uC, not simply N.
To calculate the electric field correctly, you need to divide the electric force (-45.5 N) by the charge (-3.5 x 10^-6 C):
Electric field = electric force / charge
Electric field = (-45.5 N) / (-3.5 x 10^-6 C)
Electric field ≈ 1.3 x 10^7 N/C
Now, you can calculate the force experienced by the proton using the formula:
Force = charge * electric field
Force = (+1.6 x 10^-19 C) * (1.3 x 10^7 N/C)
Force ≈ 2.08 x 10^-12 N
So, the force experienced by the proton in the same electric field is approximately 2.08 x 10^-12 N.