Take q1=23uC at (0,1), q2=16uC. at (2,0), and q3=? at (2,2). IF the force on q1 points in the -x direction, (a) what is q3 and (b) what is the magnitude of the force on q1?
I know a is 16uC
For part B I got .067 am I right
I am using Coloumbs law
k=9.0*10^9
q1=23*10^-6
q2=16*10-6
r=7
What am I doing wrong??
You have to figure each force on q1 (from q3, q3) and add them as VECTORS.
How do you do that
Josh, if you don't know how to add two ninety degree vectors, and you are now in statics, something is greatly wrong.
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/vectors/u3l1b.html
To determine the missing charge q3, we can use Coulomb's law, which states that the force between two charged objects is given by:
F = k * |q1 * q2| / r^2
where:
- F is the force between the charges
- k is the Coulomb's constant (9.0 * 10^9 Nm^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges
Given the known values:
q1 = 23 uC = 23 * 10^-6 C
q2 = 16 uC = 16 * 10^-6 C
r = 7 units
Substituting these values into the equation, we can solve for q3:
F = k * |q1 * q3| / r^2
The question states that the force on q1 points in the -x direction. Since q2 is positioned at (2,0) and q1 is positioned at (0,1), we can conclude that q3 is located at (2,2).
The distance between q1 and q3 can be calculated using the Pythagorean theorem:
d = √(x^2 + y^2) = √(2^2 + 1^2)
Using the new distance d = √(5) in the above equation, we can solve for q3:
F = k * |q1 * q3| / (√5)^2
- Substitute the known values for k, q1, F, and the new distance into the equation
- Solve for q3
Now let's calculate the magnitude of the force on q1:
F = k * |q1 * q2| / r^2
We already know the values of k, q1, q2, and r. Plug in these values and solve for F.
Double-check your calculations using the provided values and equations.