What is the value of c in the equation f(c)=0 with the funtion f(x)=9/5c +32
If f(c)=0, then 0 = 9/5c + 32
Solve for c.
-32 = 9/5 c
-160/9 = c
Please list this as MATH, not 9th grade.
Sra
To find the value of c in the equation f(c) = 0, where f(x) = (9/5)c + 32, we can substitute the value of f(x) with 0 and solve for c.
Let's set f(c) = 0:
0 = (9/5)c + 32
To isolate c, we can start by subtracting 32 from both sides:
-32 = (9/5)c
Next, we need to get rid of the fraction (9/5) by multiplying both sides by its reciprocal, which is (5/9):
(-32) * (5/9) = c
Simplifying the left side:
-160/9 = c
So, the value of c in the given equation f(c) = 0 is -160/9.