I HAVE A GARDEN THE WIDTH OF MY GARDEN IS 8FT LONGER THAN THE LENGHT OF IT ARUOUND THE GARDEN I HAVE A 4 FEET WIDE SIDEWALK. THE AREA OF THE SIDEWALK IS ABOUT 320 FEET SQUARE, WHAT ARE THE DIMENSIONS OF MY GARDEN
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To solve the problem, you would let one side of the garden be x feet. Then the longer side will be (x+8) feet. The area of the garden is therefore A1 = x(x+8) sq. ft.
COntinue this way to calculate the rectangle that includes the footpath and the garden, all expressed in terms of x and numbers. Calculate similarly the area, A2, in sq. ft.
The question suggest that A2 - A1 = 320 sq. ft. So form the equation and solve for x.
It will be a single linear equation in one unknown x, which you will need to find.
Give it a try and post your results.
To find the dimensions of the garden, we first need to calculate the area of the entire plot (including the garden and the sidewalk).
Let's assume the length of the garden is "x" feet.
Given that the width of the garden is 8 feet longer than its length, the width can be expressed as (x + 8) feet.
To calculate the total area of the plot, we add the area of the garden and the area of the sidewalk.
The area of the garden is given by the formula: length × width.
So, the area of the garden is x × (x + 8) square feet.
The sidewalk is 4 feet wide, and we know its area is 320 square feet.
Therefore, the total area of the plot (including the garden and the sidewalk) is given by the equation:
x × (x + 8) + 320 = total area
Now, we can solve this equation to find the value of "x" which represents the length of the garden.
Once we determine the value of "x," we can calculate the width of the garden by adding 8 feet to the length.
Finally, we have the dimensions of the garden - the length (x) and the width (x + 8).