Posted by **NANCY** on Thursday, August 6, 2009 at 2:02pm.

I HAVE A GARDEN THE WIDTH OF MY GARDEN IS 8FT LONGER THAN THE LENGHT OF IT ARUOUND THE GARDEN I HAVE A 4 FEET WIDE SIDEWALK. THE AREA OF THE SIDEWALK IS ABOUT 320 FEET SQUARE, WHAT ARE THE DIMENSIONS OF MY GARDEN

- MATH -
**MathMate**, Thursday, August 6, 2009 at 6:03pm
To make it easier to read, we usually type the question in lower case except for punctuation requirements.

All upper case is considered "shouting".

To solve the problem, you would let one side of the garden be x feet. Then the longer side will be (x+8) feet. The area of the garden is therefore A1 = x(x+8) sq. ft.

COntinue this way to calculate the rectangle that includes the footpath and the garden, all expressed in terms of x and numbers. Calculate similarly the area, A2, in sq. ft.

The question suggest that A2 - A1 = 320 sq. ft. So form the equation and solve for x.

It will be a single linear equation in one unknown x, which you will need to find.

Give it a try and post your results.

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