Posted by **Jon** on Thursday, August 6, 2009 at 11:34am.

Identify the polar form of the linear equation 4x+3y=10.

x=rcos(theta),y=rsin(theta)

4x+3y=4rcos(theta)+3rsin(theta)=10

r=10/(4cos(theta)+3sin(theta)

I got it wrong

- Advanced Math -
**Aayush**, Thursday, August 6, 2009 at 12:18pm
4cos(theta)+3sin(theta)=(10/r)

- Advanced Math -
**Marth**, Thursday, August 6, 2009 at 12:19pm
The only problem I can see is that you forgot a closing parentheses in your final answer. Without knowing how your answer was graded, I cannot say whether that caused you to get it wrong; but the rest of your math looks correct.

4x + 3y = 10

4rcos(theta) + 3rsin(theta) = 10

r = 10/(4cos(theta) + 3sin(theta))

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