Posted by **chrissy** on Thursday, August 6, 2009 at 11:15am.

how would i sove this problem?

x^6 + 3x^3 + 2 = 0

- math, -
**Aayush**, Thursday, August 6, 2009 at 11:31am
x^6+3x^3+2=0

It can also be written as:

(x^3)^2+3(x^3)+2=0...........(1)

Let a=(x^3), then we may rewrite equation (1) as:

a^2+3a+2=0

or,a^2+a+2a+2=0

or,a(a+1)+2(a+1)=0

or,(a+1)(a+2)=0

either,a=-1 or,a=-2

that is (x^3)=-1 or (x^3)=-2

Therefore, x=-1 or x=cube root of -2

this is the solution to your equation.

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