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August 26, 2016
Posted by **Pamela** on Wednesday, August 5, 2009 at 5:17pm.

Write the exponential form of the equation and solve the equation for x.

Does this work? Thanks!

Exponential form is 2^-3=1/8

To Check:

2^-3=1/2^3=1/8

- Algebra Help -
**MathMate**, Wednesday, August 5, 2009 at 5:31pmPlease continue with post below, you are almost there!

http://www.jiskha.com/display.cgi?id=1249473232 - Algebra Help -
**Pamela**, Wednesday, August 5, 2009 at 5:48pmx = log_ 2 2^-3

? I am lost now. I really thought I had it from what I just posted.

Exponential form is 2^-3 = 1/8 This isn't correct?

To Check:

2^-3=1/2^3=1/8 - Algebra Help -
**MathMate**, Wednesday, August 5, 2009 at 6:41pmExponential form is 2^-3 = 1/8 This isn't correct?

This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding.

You also need to do the second part: " and solve the equation for x."

You are very close to finishing, keep it up. - Algebra Help -
**Pamela**, Wednesday, August 5, 2009 at 6:49pmSolve for x i got, the exponential is the problem for me...Here is what i got for x.

To Solve:

1/8=8^-1

8=2^3

1/8=2^3^-1=8^-1

=2^-3

Log_2 1/8 = log_2 2^-3

=-3log_2 2

x =-3

To Check:

2^x=1/8= 2^-3

x=-3 - Algebra Help -
**MathMate**, Wednesday, August 5, 2009 at 8:29pmCorrect!

- Algebra Help -
**Pamela**, Wednesday, August 5, 2009 at 8:36pmNow what about the Exponential form

?

2^-3 = 1/8 This isn't correct? If not then how do i show Let x = log_2 1/8 in exponential form? - Algebra Help -
**MathMate**, Wednesday, August 5, 2009 at 8:42pm"Algebra Help - MathMate, Wednesday, August 5, 2009 at 6:41pm

Exponential form is 2^-3 = 1/8 This isn't correct?

This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding. "

The exponential form has to be correct for you to proceed with the second part, otherwise the second part will not be correct. - Algebra Help -
**Pamela**, Wednesday, August 5, 2009 at 8:45pmThank you this really helps! So I got

Exponential form is 2^-3 = 1/8

and To solve x = -3 So this is all of it? - Algebra Help -
**MathMate**, Wednesday, August 5, 2009 at 9:08pmThat's all there is to it.

If you have time, read up and understand of the identities listed earlier. You'll be glad you did when exam comes around. - Algebra Help -
**Pamela**, Wednesday, August 5, 2009 at 9:18pmThanks! You have been a BIG help! I will do that!

- Algebra Help -
**MathMate**, Wednesday, August 5, 2009 at 10:26pmIt's been a pleasure!