Monday

July 28, 2014

July 28, 2014

Posted by **coried** on Wednesday, August 5, 2009 at 3:27pm.

Radiator in a certain make needs to contain 50 liters of 40% antifreeze. The radiator now contains 50 liters of 20% antifreeze. How many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength?

- Algebra -
**drwls**, Wednesday, August 5, 2009 at 4:16pmLet X be the number of liters that must be drained and replaced with 100% antifreeze.

[0.2(50-X)+X]/50 = 0.4

Solve that for X.

- Algebra -
**bobpursley**, Wednesday, August 5, 2009 at 4:17pmYou want to double the concentration?

If you remove X liters, you remove .2X antifreeze, and .8X water.

You have left in the radiator after draining X, 10-.2X liters of pure antifreeze. You need a total of 20 liters to get 40percent antifreeze.

So you add 10+.2X of antifreeze.

You drain out 10-2X of solution.

X=10+.2X

.8X=10

x=12.5 liters

**Related Questions**

college - The radiator in a certain make of car needs to contain 20 liters of 40...

Algrbra I - Help!! I do not understand how to work these types of problems. My ...

Word Problem - It is necessary to have a 40% antifreeze solution in the radiator...

algebra - A mechanic is working on a car that has a 10 Liter radiator that is ...

Math - The radiator of a car contains 20 liters of water. Five liters are ...

Derivative-Word Problem - Volume in liters of antifreeze remaining in a leaking ...

algebra help please - Mixture Problem... An auto tech needs a radiator to have a...

Algebra - The radiator in Natalies car contains 6.3L of antifreeze and water....

MATH - i really need help on this question!! I need to solve it using a system ...

Chemistry - 5.00kg glycol, C2H4(OH)2, [this is anti-freeze!] is added to your ...