Posted by **chrissy** on Tuesday, August 4, 2009 at 12:01pm.

3x^(1/3) + 2x^(2/3) = 5

solve for x

- math -
**MathMate**, Tuesday, August 4, 2009 at 2:27pm
Use the substitution

u=x_{(1/3)}

The original equation

3x^(1/3) + 2x^(2/3) = 5

now becomes

3u + 2u² = 5

Solve by the quadratic formula for u, and finally replace u by x_{(1/3)}.

- math -
**MathMate**, Tuesday, August 4, 2009 at 2:28pm
Sorry, _{(1/3)} should read ^{(1/3)}

- math -
**MathMate**, Tuesday, August 4, 2009 at 2:29pm
I'll try it again:

x_{(1/3)} should read x^{(1/3)}

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