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April 16, 2014

April 16, 2014

Posted by **chrissy** on Tuesday, August 4, 2009 at 12:01pm.

solve for x

- math -
**MathMate**, Tuesday, August 4, 2009 at 2:27pmUse the substitution

u=x_{(1/3)}

The original equation

3x^(1/3) + 2x^(2/3) = 5

now becomes

3u + 2u² = 5

Solve by the quadratic formula for u, and finally replace u by x_{(1/3)}.

- math -
**MathMate**, Tuesday, August 4, 2009 at 2:28pmSorry,

_{(1/3)}should read^{(1/3)}

- math -
**MathMate**, Tuesday, August 4, 2009 at 2:29pmI'll try it again:

x_{(1/3)}should read x^{(1/3)}

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