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November 25, 2014

November 25, 2014

Posted by **Anonymous** on Tuesday, August 4, 2009 at 1:11am.

- math -
**drwls**, Tuesday, August 4, 2009 at 1:57amTwo out of 14 are green. That is 1/7 probability, on the first draw.

The probabilty of NOT getting green three times in a row, without replacement, is (6/7)(11/13)(10/12) = 0.6043660

The probability of getting one or more green is 1 minus that number = 0.3956

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