Sunday

December 21, 2014

December 21, 2014

Posted by **B.B.** on Monday, August 3, 2009 at 8:03am.

Answer: 36/52 18/26 9/13= 69%.

Is this right? Thanks for the help.

- Math -
**B.B.**, Monday, August 3, 2009 at 8:38amWrong question please don't answer. Thanks.

- Math -
**drwls**, Monday, August 3, 2009 at 8:39amNo, that is not right. Doesn't 69% seem too high a probability for drawing spades twice in a row?

This is a conditional probability. A key phrase is "...IF the first card was not a spade." You have to assume that the first card was NOT a spade. Then the deck before the second draw has 13 spades out of 52. The same applies to the third draw, since the drawn spades are replaced. The answer is (13/52)^2 = 1/16

- Math -
**MathMate**, Monday, August 3, 2009 at 8:44amIf we consider "without replacement", the second draw starts with only 51 cards and 13 spades.

The probability of success would be the product of the probabilities of the second and third draws, namely

(13/51)*(12/50)=26/425

- Math -
**drwls**, Monday, August 3, 2009 at 10:51amI did the with replacement case by mistake. Careless of me. Sorry

**Answer this Question**

**Related Questions**

math 157 - three cards are drawn without replacement from an ordinary deck of 52...

probability/math - Three cards are drawn without replacement from an ordinary ...

Math - Two cards are drawn without replacement from an ordinary deck of 52 ...

math - Two cards are drawn without replacement from an ordinary deck of 52 ...

Math/ Probability - Two cards are drawn without replacement from an ordinary ...

Math - Two cards are drawn without replacement from an ordinary deck of 52 ...

Math - two cards are drawn without replacement from an ordinary deck of 52 ...

Math - Two cards are drawn without replacement from an ordinary deck of 52 ...

Math - Two cards are drawn without replacement from an ordinary deck of 52 ...

math - 2 cards are drawn without replacement from an ordinary deck of 52 playing...