Post a New Question


posted by .

A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

  • Chemistry -


    molality= molestoulene/(kg benezene)

    Do you have any questions on how to do these?

  • Chemistry -

    how do you get the volume of the solution

  • Chemistry -

    and how do you get moles of toluene? please

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question