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August 28, 2014

August 28, 2014

Posted by **jakkie j** on Friday, July 31, 2009 at 3:44am.

- math -
**drwls**, Friday, July 31, 2009 at 5:20amL = 3D

D = C + 5

L + 18 = 2(C +18)

First eliminate one of the variables. I will use the first two equations to eliminate D.

L = 3(C+5) = 3C + 15

L = 2C + 18

Those two equations tell you, by setting 2C + 18 = 3C + 15, that

C = 3; so L = 24

D = 8.

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