Tuesday

November 25, 2014

November 25, 2014

Posted by **Candy** on Wednesday, July 29, 2009 at 4:47pm.

- business statistics -
**MathGuru**, Thursday, July 30, 2009 at 9:00amUsing the z-test formula to find the test statistic:

z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)

z = (230.8 - 220)/(17/√12)

Finish the calculation. Since this sample is from a normally distributed population, use a z-table to determine your p-value (the p-value is the actual level of the test statistic). Compare the p-value to 0.05 level of significance for a one-tailed test (the test is one-tailed because H1 is showing a specific direction). Determine whether or not to reject the null based on your outcome. If the null is rejected, then you conclude µ > 220. If the null is not rejected, then you cannot conclude a difference.

I hope this will help get you started.

**Answer this Question**

**Related Questions**

Statistics - Are these statements true or false? 1. The sample mean, the sample ...

statistics - How do we compute sample size fluctuations? Suppose we have a ...

business statistics - the following data values are a simple random sample form ...

statistics - IQ scores are normally distributed with a mean of 105 and a ...

statistics - Determine the 90% confidence interval for a sample, taken from a ...

statistics - Determine the 90% confidence interval for a sample, taken from a ...

sample size/ standard deviations - How do we compute sample size fluctuations? ...

statistics - A simple random sample of 60 items resulted in a sample mean of 80...

statistics - A simple random sample of 25 has been collected from a normally ...

Statistics - A simple random sample of 25 has been collected from a normally ...