Tuesday

July 29, 2014

July 29, 2014

Posted by **dedee** on Wednesday, July 29, 2009 at 4:06pm.

a). which mover provides a better deal for 2 hours of work? How did you arrive at your answer?

b). which mover provides a better deal for 15 hours of work? How did you arrive at your answer?

C). For what values h(hours) does Quick Move offer the better deal? Express your answer as an inequality. Explain how you reached your answer.

- algebra -
**MathMate**, Wednesday, July 29, 2009 at 4:20pmThe simplest way to do it is by tabulation. Create a table with the following headings:

1. hour

2. cost for Heavy-Lifters

3. cost for Quick-Move

H H-L Q-M

0 080 000

1 115 055

2 150 110

3 185 165

4 220 220

5 255 275

6 290 330

...

We can see that the cost of Quick-Move catches up with Heavy-Lifter as of the 4 hour, at which time they are equal.

Another way is to calculate the fixed charge divided by the different in hourly rate, which turns out to be

80/(55-35) = 4 hours.

The mathematical way is to formulate two expressions representing the charges.

HL(t) = 80 + 35t

QM(t) = 55t

Solve for the interval where the inequality HL(t)≤QM(t) holds true.

Your approach depends on what your teacher expects, and how comfortable you are with each method.

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