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July 29, 2016
Posted by **B.B.** on Wednesday, July 29, 2009 at 1:53pm.

- Math -
**MathMate**, Wednesday, July 29, 2009 at 2:04pm1. arrange the numbers in ascending numerical order:

{ 72, 80, 80, 82, 88, 90, 96}.

2. Find the median, which is the middle number of the list. In the given case, the middle number of 7 number is the fourth, namely 82.

{ 72, 80, 80,**82**, 88, 90, 96}

3. Find the first quartile:

Disregard the median and numbers higher than the median. For the remaining numbers, repeat step number 2, this is the first quartile. (80)

{ 72,**80**, 80 ...}.

4. Find the third quartile: repeat step 3 using the upper half of the list of numbers.

{ ... 88,**90**, 96}.

5. We should end up with the data set as follows:

{ 72,**80**, 80,**82**, 88,**90**, 96}.

The inner quartile range is the difference between the third and the fisrt quartiles, namely 90-80=10 in the given case.

Note that there are specific procedures for finding the median when there the number of numbers is even. - Math -
**B.B.**, Wednesday, July 29, 2009 at 2:51pmThank you.