Saturday
April 19, 2014

Homework Help: Chem

Posted by Lena on Monday, July 27, 2009 at 1:32am.

The question is telling me that NaOH (24.00 grams) is diluted in water (750 mL). Find the pH and pOH. This is what I did so far:

NaOH ---> Na+ + OH-

NaOH:
mass = 24.00 grams
v= 750 ml = 0.750 L
M= 40.00 grams/mol
n= 0.6000 mol
c= 0.800 mol/L

Since NaOH dissociates 100%, the concentration of OH- = the concentration of NaOH. Therefore,

pOH = -log [0.800]
= 9.69 x 10^-2

[pH][pOH] = 1 x 10^-14
pH = 1 x 10^-14 / 9.69 x 10^-12
= 1.03 x 10^-3

Did I do this correctly?

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