Saturday

February 28, 2015

February 28, 2015

Posted by **Sydney** on Saturday, July 25, 2009 at 8:59pm.

- College Algebra -
**MathMate**, Saturday, July 25, 2009 at 11:10pm(6x²-6)

=6(x²-1)

=6(x+1)(x-1)

If the above expression is the denominator of a given function, there will be two vertical asymptotes, namely at the zeroes of the given expression, at x=1 and x=-1.

The expression equals zero at these two places since 6*0=0.

**Answer this Question**

**Related Questions**

pre cal - g(x) = x^2 - x -12 / x + 1 I know the division brings it to x -2 + -10...

College Algebra - Using the 7 steps outlined in section 4.3 of your book, ...

Math - State domain, range, period, vertical asymptotes, zeros, symmetry and y-...

math - the sum of numerator and denominator is 3 less than twice the denominator...

math - 1)The area A of a triangle varies jointly as the lengths of its base b ...

math,correction please.. - (x)/(x-2) - (x+1)/(x) = (8)/(x^2-2x) I keep getting x...

Calculus - Ok so I have to find a vertical asymptote with denominator 3x^3-x-1. ...

Calculus/College Algebra - I'm so lost. We're working on limits for this ...

advance functions gr 12 - use the asymptotes and intercepts to make a quick ...

advance functions gr 12 - use the asymptotes and intercepts to make a quick ...