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Identify the conic section whose equation is given:
x2 + 10x + y2 + 12y = 60

  • math - ,

    x^2 + 10 x + (10/2)^2 + y^2 +12 y + (12/2)^2 = 60 +(10/2)^2 + (12/2)^2

    x^2 + 10 x + 25 + y^2 + 12 y + 36 = 60 + 25 + 36

    (x+5)^2 + (y+6)^2 = 121

    That is a circle with radius 11 centered at (-5,-6).

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