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December 18, 2014

December 18, 2014

Posted by **Melissa** on Friday, July 24, 2009 at 7:41pm.

equally the cost of a $200,000 airplane. The members

want to find five more people to join the club so that the

cost per person will decrease by $2000. How many members

are currently in the club?

- algebra repost -
**Marth**, Friday, July 24, 2009 at 7:44pmlet x = the number of members currently in the club

200,000/x = 200,000/(x+5) + 2000

Multiply to eliminate fractions.

200,000(x+5) = 200,000x + 2000(x)(x+5)

200,000x + 1,000,000 = 200,000x + 2000x^2 + 10,000x

1,000,000 = 2000x^2 + 10,000x

2000x^2 + 10,000x - 1,000,000 = 0

Divide by 2000.

x^2 + 5x - 500 = 0

(x+25)(x-20) = 0

x = 20, -25

The answer of x=-25 does not make sense in the context, so we are left with x=20 people.

- algebra repost -
**Anonymous**, Thursday, October 8, 2009 at 2:00pmSharing cost. The members of a flying club plan to share

equally the cost of a $200,000 airplane. The members

want to find five more people to join the club so that the

cost per person will decrease by $2000. How many members

are currently in the club?

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