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October 1, 2014

October 1, 2014

Posted by **Alex** on Friday, July 24, 2009 at 3:45pm.

Here is my attempted work. What am I doing incorrect?

n = m x M

= 0.26g x 18.01 g/mol

= 4.6826 mols

PV = nRT

Rearrange to get:

P = nRT/V

= (4.6826 mols)(8.3145 J/K⋅mol)(60ºC)/ 0.11 mL

= 21236.44 atm

Therefore, the vapour pressure of water at this temperature is 21236.44 atm.

- chemistry -
**DrBob222**, Friday, July 24, 2009 at 3:55pmYou may have other mistakes, also, but 60 degrees C must be substituted into the equation as Kelvin and volume as liters. And if you want the answer to be in atm, then R must be 0.08205.

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