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March 29, 2015

March 29, 2015

Posted by **Shellie** on Friday, July 24, 2009 at 1:59pm.

m(t) = Moe(-ln2/5730) is a starting point

- Pre Calculus -
**MathMate**, Saturday, July 25, 2009 at 8:39amLet

P_{14}= fraction of C_{14}found in sample (0.56)

T_{1/2}= radioactive half life (5730 years)

Then

Age of sample

=T_{1/2}*(ln(P_{14})/ln(0.5)) (Before present)

=5730*(ln(0.56)/ln(0.5)) (BP)

=4793 (BP)

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