Pre Calculus
posted by Shellie on .
The burial cloth of an Egyptian mummy is estimated to contain 56% of the carbon14 it contained originally. How long ago was the mummy buried? (the halflife of carbon14 is 5730). Please round the answer to the nearest tenth. I have figured that:
m(t) = Moe(ln2/5730) is a starting point

Let
P_{14} = fraction of C_{14} found in sample (0.56)
T_{1/2} = radioactive half life (5730 years)
Then
Age of sample
=T_{1/2}*(ln(P_{14})/ln(0.5)) (Before present)
=5730*(ln(0.56)/ln(0.5)) (BP)
=4793 (BP)