Posted by Shellie on Friday, July 24, 2009 at 1:59pm.
Let
P14 = fraction of C14 found in sample (0.56)
T1/2 = radioactive half life (5730 years)
Then
Age of sample
=T1/2*(ln(P14)/ln(0.5)) (Before present)
=5730*(ln(0.56)/ln(0.5)) (BP)
=4793 (BP)
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