Posted by Melissa on .
©ø¡î27
= 9¡î3
is this correct

algebra 
Melissa,
sorry I did not realize sqrt could not be read
It should read
sqrt27 with a little three on the outside.
and my answer is
9sqrt3 
algebra 
Marth,
sqrt(27)
First, you have the square root of a negative. Use i to express the sqrt(1):
i*sqrt(27)
Consider that 27 = 3^3, or 9*3.
= i*sqrt(9*3)
The sqrt(9) is 3, so you have 3i*sqrt(3)