Posted by Melissa on Friday, July 24, 2009 at 1:45pm.
©ø¡î27
= 9¡î3
is this correct

algebra  Melissa, Friday, July 24, 2009 at 1:58pm
sorry I did not realize sqrt could not be read
It should read
sqrt27 with a little three on the outside.
and my answer is
9sqrt3

algebra  Marth, Friday, July 24, 2009 at 7:47pm
sqrt(27)
First, you have the square root of a negative. Use i to express the sqrt(1):
i*sqrt(27)
Consider that 27 = 3^3, or 9*3.
= i*sqrt(9*3)
The sqrt(9) is 3, so you have 3i*sqrt(3)
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