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July 24, 2014

July 24, 2014

Posted by **Matrix School 1** on Friday, July 24, 2009 at 12:06pm.

calculate the angular magnification of the telescope and also determine the distance between the two lenses.

- Geometric & Wave Optics -
**MathMate**, Saturday, July 25, 2009 at 9:16amFor astronomical telescopes, the objects are at infinity, so parallel rays reach the objective. The eye-piece is therefore placed at a distance from the objective equal to the focal length. At this location, the magnification is equal to the quotient of the focal lengths.

Magnification

= 100 cm / 8 cm

= 12.5 times.

Note: eye-pieces usually have focal lengths in the millimetres range, so it is likely that the focal length of the eye-piece is 8 mm., in which case

Magnification

= 100 cm /8 mm

= 125 times.

- Geometric & Wave Optics -
**Anonymous**, Thursday, February 3, 2011 at 3:25pm1. An object,30mm high ,is 90mm from a convex lens. The focal length is 60mm det the positive height an nature of the image. Draw an accurate diagram for the formation of the image. 2.calculate its magnification?

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