Posted by Math on Friday, July 24, 2009 at 1:22am.
make a 'time-graph' and label points 0,(now), 18,24 (the rate changes here), 30, and 36.
place 10000 at 0
1800 at 18 and 2400 at 30
you want to bring all three money values up to time-point 36
the 1800 is charged a rate of .115/12 for 6 months and then .1074/12 for the next 12 months.
its value at 36 = 1800(1+.115/12)^6(1+.1074/12)^12
= $2121.10
the 2400 is charged .1074/12 for 6 months
its value is 2400(1+.1074/12)^6
= $2531.80
The original debt at 36 has a value of
10000(1+.115/12)^24(1+.1074/12)^12
= 13990.97
so the amount owing is
13990.97 - 2531.80 - 2121.10
= 9338.07
(please check my arithmetic)
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