Monday
July 6, 2015

Homework Help: chem

Posted by Lena on Thursday, July 23, 2009 at 10:54pm.

Calculate the [h3o+] and [oh-], pH and the percent dissociation for both 0.25 mol/L HCl and 0.25 mol/L HCN.

0.25 mol/L HCL
[H+] = 0.25 mol/L
[OH-] = 1 x 10^-14 / 0.25 = 4 x 10^-14
pH = 0.60
% dissociation = ?
( I dont know how to figure out percent dissociation)

For the HCN I thought I would do the same thing since there is also 0.25 mol/L of it but in the solution there is the number 1.2 x 10^ -5 and I dont understand where it came from. Could someone please help? thanks :)

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