Posted by Mike on Thursday, July 23, 2009 at 6:07pm.
Solve the matrix equation AX =B for X using:
A= [ 2 3] B= [4 ]
[ 1 5] [2 ]
(theres a blank space between the 4 and the 2)

Finite Math  Reiny, Thursday, July 23, 2009 at 6:37pm
I found the inverse of A to be
5/13 3/13
1/13 2/13
so
A^{1} A X = A^{1</sup B
X =
│ 5/13 3/13││4│
│1/13 2/13││2│
=
│2│
│0│}

Finite Math  Reiny, Thursday, July 23, 2009 at 7:23pm
that doesn't look like I intended.
let's try that again
so
A^{1} A X = A^{1} B
X =
│ 5/13 3/13││4│
│1/13 2/13││2│
=
│2│
│0│
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