Posted by **Mike** on Thursday, July 23, 2009 at 6:07pm.

Solve the matrix equation AX =B for X using:

A= [ 2 -3] B= [4 ]

[ 1 5] [2 ]

(theres a blank space between the 4 and the 2)

- Finite Math -
**Reiny**, Thursday, July 23, 2009 at 6:37pm
I found the inverse of A to be

5/13 3/13

-1/13 2/13

so

A^{-1} A X = A^{-1</sup B
X =
│ 5/13 3/13││4│
│-1/13 2/13││2│
=
│2│
│0│
}

- Finite Math -
**Reiny**, Thursday, July 23, 2009 at 7:23pm
that doesn't look like I intended.

let's try that again

so

A^{-1} A X = A^{-1} B

X =

│ 5/13 3/13││4│

│-1/13 2/13││2│

=

│2│

│0│

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