Friday
August 29, 2014

Homework Help: Algebra

Posted by Audrey on Wednesday, July 22, 2009 at 9:25pm.

The function w(x) = 0.01x^2 + 0.27x + 8.60 can be used to estimate the number of selfemployed
workers in the U.S., in millions, x years after 1980. How many self-employed workers
were there in the year 1995?

A. 9.8 million
B. 10.4 million
C. 11.15 million
D. 14.9 million

I think the answer is B 10.4 million, but not 100%. Can someone please explain? Thank you

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

algebra - the function w(x)=-0.01x^2+0.27x+9.20 can be used to estimate the ...
Algebra - The population of Australia in x years after 1980 can be modeled by ...
Intermediate algebra - The number of trout in America, since 1970, is given by ...
algebra - The projected number of men and women enrolled in US colleges, in ...
Algebra - For 1980 through 1990, the average weekly earnings (in dollars)for ...
algebra - A certain country's population P(t), in millions, t years after 1980 ...
Math - Solve. The population of a particular country was 29 million in 1980; in ...
Algebra one story problem help please. - in 1993, 2.00 Million females ...
Calculus - The population of a region is growing exponentially. There were 40 ...
Biology - PLEASE HELP!!!! 1. How many millions of years ago did sharks first ...

Search
Members