Posted by Audrey on .
The function w(x) = – 0.01x^2 + 0.27x + 8.60 can be used to estimate the number of selfemployed
workers in the U.S., in millions, x years after 1980. How many selfemployed workers
were there in the year 1995?
A. 9.8 million
B. 10.4 million
C. 11.15 million
D. 14.9 million
I think the answer is B 10.4 million, but not 100%. Can someone please explain? Thank you

Algebra 
MathMate,
x years after 1980 means that for 1981, x=1, 1982, x=2,.... for 1990, x=10, and 1995, x=15.
If you substitute 15 for x in the function w(x), you will find the population in millions.
Post your choice of answer for verification if you wish. 
Algebra 
Audrey,
Thanks I chose B 10.4 Million. I am confident that this is the correct answer. Am I correct?

Algebra 
MathMate,
Well done, that's correct!