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Algebra

posted by on .

The function w(x) = – 0.01x^2 + 0.27x + 8.60 can be used to estimate the number of selfemployed
workers in the U.S., in millions, x years after 1980. How many self-employed workers
were there in the year 1995?

A. 9.8 million
B. 10.4 million
C. 11.15 million
D. 14.9 million

I think the answer is B 10.4 million, but not 100%. Can someone please explain? Thank you

  • Algebra - ,

    x years after 1980 means that for 1981, x=1, 1982, x=2,.... for 1990, x=10, and 1995, x=15.
    If you substitute 15 for x in the function w(x), you will find the population in millions.
    Post your choice of answer for verification if you wish.

  • Algebra - ,

    Thanks I chose B 10.4 Million. I am confident that this is the correct answer. Am I correct?

  • Algebra - ,

    Well done, that's correct!

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