Saturday

October 25, 2014

October 25, 2014

Posted by **Britney** on Wednesday, July 22, 2009 at 9:22pm.

Find all of the zeros of the polynomial function and state the multiplicity of each.

f (x) = (x^2 – 16)^2

A. – 4 with multiplicity 2 and 4 with multiplicity 2

B. – 4i with multiplicity 2 and 4i with multiplicity 2

C. 4 with multiplicity 2

D. 4 with multiplicity 4

I say it's A or C but leaning towards A? Any suggestions? Thanks!

- Algebra -
**MathMate**, Wednesday, July 22, 2009 at 9:42pm(x²-16)²

=(x+4)²(x-4)²

What can you say with the number of distinct zeroes?

What can you say about the multiplicity of each zero?

The order of the polynomial being 4, what can you say about the total number of zeros, all multiplicities taken into account?

If the answer is either A or C, which one would you choose?

- Algebra -
**Britney**, Wednesday, July 22, 2009 at 9:52pmI was thinking (A) because of the -16, and we need a - number to get that. Is this right?

- Algebra -
**MathMate**, Wednesday, July 22, 2009 at 11:40pmA is correct.

There are two distinct roots, so C and D are out of the question.

The zeroes are real, so B is out of the question. That leaves us with A.

**Answer this Question**

**Related Questions**

Algebra - Find all of the zeros of the polynomial function and state the ...

Algebra - Find all of the zeros of the polynomial function and state the ...

Algebra - Find all of the zeros of the polynomial function and state the ...

Algebra - Find the zeros of the polynomial function and state the multiplicity ...

Algebra - Find the zeros of the polynomial function and state the multiplicity ...

college algebra--please help - Form a polynomial f(x) with real coefficients ...

algebra - find all real zeros and their multiplicity of the polynomial function ...

algebra - find all real zeros and their multiplicity of the polynomial function ...

ap algebra - Can you please help me with these problems I dont understand them? ...

ap algebra - can you check my answers please? Find the zeros for the polynomial ...