Posted by **Matrix School 2** on Wednesday, July 22, 2009 at 3:03pm.

when an object is placed 10cm away from a lens; it is found that the formed is 6cm behind the object on the same side of the lens.

Determine the focal lenght of the lens.

solution

1/v + 1/u = 1/f

u=10cm, v=6cm, f=?

6+10/60 = 1/f

70/60 = 1/f

by cross multiply we have

70 x f = 60 x 1

70 x f = 60

f = 60/70 = 6/7 ans.

- Geometric & Wave Optics -
**bobpursley**, Wednesday, July 22, 2009 at 8:32pm
see other.

## Answer this Question

## Related Questions

- Geometric & Wave Optics Correction - when an object is placed 10cm away from a ...
- calculus problem - the thin lens equation in physics is 1/s+1/S=1/f where s is ...
- Physics ( optics) - A simple camera telephoto lens consists of two lenses. The ...
- marymount academy - 1.An object 2.5cm high is placed 10cm from a converging lens...
- Physics - An object is placed 30mm in front of a lens. An image of the object is...
- Physics - An object is placed to the left of a lens, and a real image is formed ...
- Physics - A simple camera telephoto lens consists of two lenses. The objective ...
- Physics - A simple camera telephoto lens consists of two lenses. The objective ...
- Physics - An object, that is 3.25 mm high is placed 16 cm in front of a lens. ...
- Science Important - 1. A toy of height 18.4 cm is balanced in front of a ...