Math
posted by Katie on .
Please help me, thank you.
A 100 kg astronaut is standing on the outside surface of a 4.50 x 10^4 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. What happens to the spacecraft?

multiply (simplified fraction)
8/3*(7/1) 
that's not right can someone please help.

I believe this is a case of conservation of momentums, namely zero since both objects were stationary to start with.
M_{1}V_{1} + M_{2}V_{2} = 0
100*8 + 45000*V_{2} = 0
V_{2}
= 100*8/45000
= 0.0178 m/s.
Answer: The spaceship moves at 0.0178 in the opposite direction as the astronaut. 
Erratum:
Answer: The spaceship moves at 0.0178 m/s in the opposite direction as the astronaut.