posted by Katie on .
Please help me, thank you.
A 100 kg astronaut is standing on the outside surface of a 4.50 x 10^4 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. What happens to the spacecraft?
multiply (simplified fraction)
that's not right can someone please help.
I believe this is a case of conservation of momentums, namely zero since both objects were stationary to start with.
M1V1 + M2V2 = 0
100*8 + 45000*V2 = 0
= -0.0178 m/s.
Answer: The spaceship moves at 0.0178 in the opposite direction as the astronaut.
Answer: The spaceship moves at 0.0178 m/s in the opposite direction as the astronaut.