Posted by **Katie** on Tuesday, July 21, 2009 at 10:14pm.

Please help me, thank you.

A 100 kg astronaut is standing on the outside surface of a 4.50 x 10^4 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. What happens to the spacecraft?

- Math -
**connie (lost)**, Tuesday, July 21, 2009 at 10:19pm
multiply (simplified fraction)

-8/3*(7/1)

- Math -
**Katie**, Tuesday, July 21, 2009 at 10:22pm
that's not right can someone please help.

- Math -
**MathMate**, Tuesday, July 21, 2009 at 11:08pm
I believe this is a case of conservation of momentums, namely zero since both objects were stationary to start with.

M_{1}V_{1} + M_{2}V_{2} = 0

100*8 + 45000*V_{2} = 0

V_{2}

= -100*8/45000

= -0.0178 m/s.

Answer: The spaceship moves at 0.0178 in the opposite direction as the astronaut.

- Math -
**MathMate**, Tuesday, July 21, 2009 at 11:08pm
Erratum:

Answer: The spaceship moves at 0.0178 **m/s** in the opposite direction as the astronaut.

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