Post a New Question

Math

posted by on .

Please help me, thank you.

A 100 kg astronaut is standing on the outside surface of a 4.50 x 10^4 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. What happens to the spacecraft?

  • Math - ,

    multiply (simplified fraction)

    -8/3*(7/1)

  • Math - ,

    that's not right can someone please help.

  • Math - ,

    I believe this is a case of conservation of momentums, namely zero since both objects were stationary to start with.
    M1V1 + M2V2 = 0
    100*8 + 45000*V2 = 0
    V2
    = -100*8/45000
    = -0.0178 m/s.
    Answer: The spaceship moves at 0.0178 in the opposite direction as the astronaut.

  • Math - ,

    Erratum:
    Answer: The spaceship moves at 0.0178 m/s in the opposite direction as the astronaut.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question