Posted by Lena on Sunday, July 19, 2009 at 2:10pm.
0.500 mol of SO2, 0.100 mol of O2 and 0.700 mol of SO3 re intorduced simutaneously into a 1.00 L vessel at 1000 K. For the equillibirum, 2SO2 (g) + O2(g) <---> 2SO3(g), the value of Kc at 1000K is 280. Show mathemtically that the mixture is NOT at equillibrium.
This is what I did:
Kc = [0.700]^2/[0.500]^2[0.100]
Therefore the mixture is not a equillibrium because in order to be at equallibrium, the mixture must have a Kc value of 280.
Did I do this correctly?
- Chemistry - DrBob222, Sunday, July 19, 2009 at 3:35pm
Looks good to me. Can you look at the 19.6 versus 280 and say that the reaction will proceed to the left or to the right?
- Chemistry - Lena, Sunday, July 19, 2009 at 3:39pm
that is the second part of the question; figuring out whether the reaction will move to the left or right. Im not too sure how to figure that out.
- Chemistry - Lena, Sunday, July 19, 2009 at 3:41pm
is the 1000 k, 1000 kelvin? :S
- Chemistry - DrBob222, Sunday, July 19, 2009 at 4:30pm
Yes, 1000 K is 1000 Kelvin.
For part b, look at the Kc expression you wrote first.
Kc = (SO3)^2/(SO2)^2(O2) = 280
Now look at the expression and ask yourself this. To get a smaller number than 280 (in this case 19.6), will the numerator get larger or smaller and will the denominator get larger or smaller. Well, the ONLY way to get a smaller number than Kc is for the numerator to become smaller and/or the denominator to become larger (or both). That tells you which direction the reaction must go.
- Chemistry - Lena, Sunday, July 19, 2009 at 4:58pm
I want to turn the 19.6 into 280 and in order to do that I must make the numerator larger and the numerator is the SO3 so therefore the reaction will move to the left?
- Chemistry - DrBob222, Sunday, July 19, 2009 at 5:06pm
Your reasoning is superb but the answer is not. Here is the reaction.
2SO2 + O2 ==> 2SO3
So you want 19.6 to become larger (to 280). You are correct on that point. To turn the number into a larger number you want the numerator (SO3) to get larger (you are correct) and you want the denominator to get smaller (you are correct there). So now look at the equation. You want SO3 to get larger, you want SO2 and O2 to get smaller, the ONLY way it can do that is to shift the reaction to the right for that is the only way SO2 and O2 are used up(making them smaller) and SO3 is formed (making it larger).
- Chemistry - Lena, Sunday, July 19, 2009 at 5:08pm
Ohh. I understand now. Thank you so much :)
Answer this Question
- Chemistry - At a certain temperature, 0.700 mol of SO3 is placed in a 3.50-L ...
- chemistry - An equilibrium mixture of SO2,SO3 and O2 gases is maintained in a 11...
- Chemistry - At a particular temp, K = 1.6 x 10^-5 for the reaction: 2SO3(g) <...
- chem - at a certain temperature, .700 mol of SO3 is place in a 4.50-L container...
- Chemistry - An equilibrium mixture of SO2, O2, and SO3 at 1000 K contains the ...
- chemistry - An equilibrium mixture of SO2, O2, and SO3 at 1000 K contains the ...
- chemistry - hi i have difficulty in this question.any help would be much ...
- CHEMISTRY - At a certain temperature , 0.960 mol of SO3 is placed in a 3.50 L ...
- Chemistry - At a particular temperature, 13.7 mol of SO3 is placed into a 3.9-L ...
- Chem 2 help - At a certain temperature, 0.800 mol of SO3 is placed in a 2.00-L ...