Please help me! Thank-you!
Calculate the concentration, in moles per liter, of a fertilizer solution if 500.0 mL of the solution contains 1.84 g of copper sulphate, CuSO4.
Just remember the definition of molarity.
M = # moles/Liter of solution.
How many moles do you have? 1.84 g/molar mass CuSO4.
How many liters do you have? 0.500 L.
Done.
Okay thank-you!
When 5.0g of copper reacts with excess silver nitrate slivermetal and copper nitrate are produced what is the theoretical yield of sliver in this reaction?
To calculate the concentration of a solution, you need to know the mass of the solute (in this case, copper sulphate) and the volume of the solution. The concentration is typically expressed in moles per liter (M or mol/L). Here's how you can determine the concentration of the fertilizer solution containing copper sulphate:
1. Convert the mass of copper sulphate from grams to moles. To do this, divide the mass of copper sulphate by its molar mass. The molar mass of CuSO4 can be found by adding up the atomic masses of its constituent elements: Cu (63.55 g/mol) + S (32.07 g/mol) + 4O (16.00 g/mol) = 159.61 g/mol.
So, 1.84 g of CuSO4 is equal to 1.84 g / 159.61 g/mol = 0.01153 mol.
2. Convert the volume of the solution from milliliters to liters. To do this, divide the volume in milliliters by 1000.
So, 500.0 mL is equal to 500.0 mL / 1000 = 0.5 L.
3. Finally, calculate the concentration by dividing the moles of copper sulphate by the volume of the solution:
Concentration (in mol/L) = 0.01153 mol / 0.5 L = 0.02306 mol/L.
Therefore, the concentration of the fertilizer solution is approximately 0.02306 moles per liter (or 0.02306 M).