Posted by Jerry on Saturday, July 18, 2009 at 11:56am.
You can probably use a one-sample t-test for this data. You'll need to calculate the mean and standard deviation. Here's a t-test formula:
t = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)
Hypotheses:
Ho: µ = 24 -->null hypothesis
Ha: µ does not equal 24 -->alternate hypothesis
Once you do the calculations, use a t-table to determine the cutoff to reject the null at .05 level of significance for a two-tailed test using 7 degrees of freedom (df = n - 1 = 8 - 1 = 7).
Does the test statistic exceed the cutoff (critical) value from the table? If it does not, you cannot reject the null and conclude a difference. If it does, then reject the null and conclude a difference.
I hope this will help.
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