Posted by **steve** on Thursday, July 16, 2009 at 5:02pm.

the domain and range of f(x)=(e^-x)-2

- math -
**Marth**, Thursday, July 16, 2009 at 5:08pm
Start with the base function: y=e^x.

The range of y=e^x is (0, infinity).

If you have y=e^-x, that flips the function over the y axis, which does not change the range.

Now factor in the -2. That shifts the function down, so subtract 2 from the range: (-2, infinity)

- math -
**Marth**, Thursday, July 16, 2009 at 5:10pm
Oops, forgot the domain.

e^x exists for all real values of x, so e^-x does also.

Therefore, the domain is (-infinity, infinity)

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