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September 1, 2014

September 1, 2014

Posted by **SALINA** on Thursday, July 16, 2009 at 2:34pm.

- MATH -
**Marth**, Thursday, July 16, 2009 at 2:43pmlet x = the width

let x+3 = the length

The area of a rectangle is length*width

x(x+3) = 54

x^2 + 3x = 54

x^2 + 3x - 54 = 0

(x+9)(x-6) = 0

x = 6, -9

A negative answer is irrelevant for this problem - the dimensions cannot be negative.

x = 6

x+3 = 9

The width is 6, and the length is 9.

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