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March 29, 2015

March 29, 2015

Posted by **Rachale** on Thursday, July 16, 2009 at 1:34am.

Vertical asymptotes x = -4, x = 5;

x-intercept (-2, 0)

- Algebra -
**MathMate**, Thursday, July 16, 2009 at 6:50amTry

f(x)=(x+2)/((x+4)(x-5))

the term x+2 will give a x-intercept at x=-2, the denominator gives vertical asymptotes at x=-4 and 5.

See http://i263.photobucket.com/albums/ii157/mathmate/rational.png

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