I have many equations that need to be net ionic balanced

1. Al(NO3)3 + NH3 --> ??

2. Fe(NO3)3 + NH3 --> ??

3. Mn(NO3)2 + NH3 --> ??

^^ All aqueous

Products?

1. probably Al(OH)3 + NO3^-
2. probably Fe(OH)3 + NO3^-
3. probably MnO(OH)2 + NO3^-

Each metal ion in the question is surrounded by six H2O molecules forming Hexaaquo complexes. The link below gives a detailed description of the reactions between the original aquo complex and NH3 for several ions, including Al(H2O)6^3+, Fe(H2O)6^3+, and Mn(H2O)6^2+:

http://www.chemguide.co.uk/inorganic/complexions/aquanh3.html

To balance net ionic equations, we need to first write the balanced molecular equation, then the complete ionic equation, and finally the net ionic equation. Let's work through each equation step by step:

1. Al(NO3)3 + NH3 →

First, write the balanced molecular equation:
Al(NO3)3 + 3NH3 → Al(NH3)3 + 3NO3

Next, write the complete ionic equation by separating all the strong electrolytes into their respective ions:
Al3+ + 3NO3- + 3NH3 → Al(NH3)3 + 3NO3-

Finally, write the net ionic equation by removing the spectator ions (the ions that appear on both sides of the equation unchanged):
Al3+ + 3NH3 → Al(NH3)3

2. Fe(NO3)3 + NH3 →

First, write the balanced molecular equation:
Fe(NO3)3 + 3NH3 → Fe(NH3)3 + 3NO3

Next, write the complete ionic equation:
Fe3+ + 3NO3- + 3NH3 → Fe(NH3)3 + 3NO3-

Finally, write the net ionic equation:
Fe3+ + 3NH3 → Fe(NH3)3

3. Mn(NO3)2 + NH3 →

First, write the balanced molecular equation:
Mn(NO3)2 + 2NH3 → Mn(NH3)2 + 2NO3

Next, write the complete ionic equation:
Mn2+ + 2NO3- + 2NH3 → Mn(NH3)2 + 2NO3-

Finally, write the net ionic equation:
Mn2+ + 2NH3 → Mn(NH3)2

These are the net ionic balanced equations for each of the given reactions.

To balance these net ionic equations, you need to follow a few steps:

Step 1: Write the balanced molecular equation for the given chemical reaction.

Step 2: Write the complete ionic equation by breaking up all the aqueous compounds into their individual ions.

Step 3: Identify and cancel out spectator ions to obtain the net ionic equation.

Let's go through each equation and balance them:

1. Al(NO3)3 + NH3 → ??

Step 1: The balanced molecular equation is:
Al(NO3)3 + 3NH3 → Al(NH3)3 + 3NO3-

Step 2: The complete ionic equation is:
Al3+ + 3NO3- + 3NH3 → Al(NH3)3 + 3NO3-

Step 3: The net ionic equation is:
Al3+ + 3NH3 → Al(NH3)3

2. Fe(NO3)3 + NH3 → ??

Step 1: The balanced molecular equation is:
Fe(NO3)3 + 3NH3 → Fe(NH3)3 + 3NO3-

Step 2: The complete ionic equation is:
Fe3+ + 3NO3- + 3NH3 → Fe(NH3)3 + 3NO3-

Step 3: The net ionic equation is:
Fe3+ + 3NH3 → Fe(NH3)3

3. Mn(NO3)2 + NH3 → ??

Step 1: The balanced molecular equation is:
Mn(NO3)2 + 2NH3 → Mn(NH3)2 + 2NO3-

Step 2: The complete ionic equation is:
Mn2+ + 2NO3- + 2NH3 → Mn(NH3)2 + 2NO3-

Step 3: The net ionic equation is:
Mn2+ + 2NH3 → Mn(NH3)2

Remember to always check the charges and ensure they are balanced on both sides of each equation.