m2a=m2g-m1a
m2a+m1a=m2g
a= m2g/(m1+m2)
I got this
m2a=m2g-m1a
m2a + m1 a = m2g-m1a + m1 a
m2 a + m1 a = m2g
(m2 a + m1 a = m2g(m2 + m1)^-1 = a + a = (m2 + m1)^-1 m2g
a + a = (m2 + m1)^-1 m2g
2a = (m2 + m1)^-1 m2g
(2a = (m2 + m1)^-1 m2g)2^-1 = a = (2(m2 + m1))^-1 m2g
a = (2(m2 + m1))^-1 m2g
Please show me what I did wrong.
Thank You!
At the step "m2 a + m1 a = m2g," you can factor out an a using the distributive property:
a(m2 + m1) = m2g
Now divide both sides by (m2 + m1):
a = m2g / (m2 + m1)
thank you so much
Based on your calculations, it seems like you are trying to solve for the value of "a" in the equation m2a = m2g - m1a. However, there are some errors in your calculations.
Let's start with the equation m2a = m2g - m1a. To solve for "a," we can rearrange the equation as follows:
m2a + m1a = m2g
(a)m2 + (a)m1 = m2g
(a)(m2 + m1) = m2g
Now, to isolate "a," we can divide both sides of the equation by (m2 + m1):
a = m2g / (m2 + m1)
So, the correct expression for "a" is a = m2g / (m2 + m1).
It seems that there might have been some confusion in your calculations. Here's how you can simplify the equation correctly:
m2a + m1a = m2g - m1a + m1a
m2a + m1a = m2g
Then, factor out the common terms involving "a":
(a)(m2 + m1) = m2g
Finally, divide both sides by (m2 + m1) to solve for "a":
a = m2g / (m2 + m1)
So, the correct expression for "a" is indeed a = m2g / (m2 + m1).
I hope this clarifies the confusion and helps you understand the correct solution. Let me know if you have any further questions!