m2a=m2g-m1a

m2a+m1a=m2g
a= m2g/(m1+m2)

I got this

m2a=m2g-m1a

m2a + m1 a = m2g-m1a + m1 a

m2 a + m1 a = m2g

(m2 a + m1 a = m2g(m2 + m1)^-1 = a + a = (m2 + m1)^-1 m2g

a + a = (m2 + m1)^-1 m2g
2a = (m2 + m1)^-1 m2g

(2a = (m2 + m1)^-1 m2g)2^-1 = a = (2(m2 + m1))^-1 m2g

a = (2(m2 + m1))^-1 m2g

Please show me what I did wrong.
Thank You!

At the step "m2 a + m1 a = m2g," you can factor out an a using the distributive property:

a(m2 + m1) = m2g

Now divide both sides by (m2 + m1):

a = m2g / (m2 + m1)

thank you so much

Based on your calculations, it seems like you are trying to solve for the value of "a" in the equation m2a = m2g - m1a. However, there are some errors in your calculations.

Let's start with the equation m2a = m2g - m1a. To solve for "a," we can rearrange the equation as follows:

m2a + m1a = m2g
(a)m2 + (a)m1 = m2g
(a)(m2 + m1) = m2g

Now, to isolate "a," we can divide both sides of the equation by (m2 + m1):

a = m2g / (m2 + m1)

So, the correct expression for "a" is a = m2g / (m2 + m1).

It seems that there might have been some confusion in your calculations. Here's how you can simplify the equation correctly:

m2a + m1a = m2g - m1a + m1a
m2a + m1a = m2g

Then, factor out the common terms involving "a":

(a)(m2 + m1) = m2g

Finally, divide both sides by (m2 + m1) to solve for "a":

a = m2g / (m2 + m1)

So, the correct expression for "a" is indeed a = m2g / (m2 + m1).

I hope this clarifies the confusion and helps you understand the correct solution. Let me know if you have any further questions!