Algebra
posted by Crystal on .
Please solve the inequality
.04 x + .06(12000x) >= 650
.04x + 720  .06x ¡Ý 650
.02x ¡Ý 70
x ¡Ý 70/.02
x ¡Ý 3500
I think this is wrong and what is below is correct? Which is right? Thanks!
.04x + 720  .06x ¡Ý 650
.02x ¡Ü 70
x ¡Ü 70/.02
x ¡Ü 3500

.04x + 720  .06x ¡Ý 650
.02x <= 70
x < = 70/.02
x < = 3500
Or do the sign go the other way like this?
.04x + 720  .06x ¡Ý 650
.02x > = 70
x > = 70/.02
x > = 3500
Which would be the solution to solve this inequality?
.04 x + .06(12000x) >= 650 
see my final reply to
http://www.jiskha.com/display.cgi?id=1247546252