Please solve the inequality

.04 x + .06(12000-x) >= 650

.04x + 720 - .06x ≥ 650

-.02x ≥ -70
x ≥ -70/-.02
x ≥ 3500

Shouldn't the answer be less than or = to?

yes, of course you are right.

When dividing by a negative we have to reverse the inequality sign.

Time for my third cup of coffee.

To solve the given inequality, let's simplify it step by step:

First, distribute the 0.06:

0.04x + 0.06(12000) - 0.06x >= 650

Now simplify:

0.04x + 720 - 0.06x >= 650

Combine like terms:

0.04x - 0.06x + 720 >= 650

-0.02x + 720 >= 650

Next, isolate the x variable by subtracting 720 from both sides:

-0.02x + 720 - 720 >= 650 - 720

-0.02x >= -70

Now, divide both sides of the inequality by -0.02 (remember to flip the inequality sign when dividing by a negative number):

(-0.02x)/(-0.02) <= -70 / (-0.02)

x <= 3500

So, the solution to the inequality is x <= 3500.