Posted by Anonymous on Monday, July 13, 2009 at 7:29pm.
Look at the equation. Base + acid = salt + water.
NaOH + HC2H3O2 ==> NaC2H3O2 + H2O
Calculate the moles NaOH to start.
Calculate the moles HC2H3O2 to start. I haven't done the calculation but I assume that the HC2H3O2 will be in excess and all of the NaOH will be used. So you end up with a buffered solution, which in this case is a weak acid (HC2H3O2) and its salt (in this case NaC2H3O2.
Now use the Henderson-Hasselbalch equation,
pH = pKa + log (base/acid) to calculate pH.
Related Questions
chemistry - What is the pH of the solution created by combining 2.80 mL of the 0...
chem lab (webwork) - What is the pH of the solution created by combining 1.80 mL...
CHEMISTRY (WEBWORK) - What is the pH of the solution created by combining 1.20 ...
chemistry - What is the pH of the solution created by combining 0.80 mL of the 0...
chemistry - how do you solve this? What is the pH of the solution created by ...
chem - I got part 1: What is the pH of the solution created by combining 1.10 mL...
chemistry - how do you solve this What is the pH of the solution created by ...
Chem - I don't get how to do this: What is the pH of the solution created by...
chemistry - What is the pH of the solution created by combining 11.50 mL of the ...
chemistry - What is the pH of the solution created by combining 2.80 mL of the 0...
For Further Reading
