Posted by DrFunk on Monday, July 13, 2009 at 1:10pm.
Call base = B (acetate ion).
Call acid = A (acetic acid).
A + B = 0.1 M
pH = pKa + log (B/A).
Two equations and two unknowns. Solve for A and B.
You know pH and pKa, so solve for B/A.
Then A + B = 0.1
That is the first part of the problem.
For the second part, recognize that
HCl + B^- ==>A + Cl^- (HB is the acid, A).
You know B and you know how much HCl is added, so redo the Henderson-Hasselbalch equation to solve for the new pH.
Post your work if you get stuck.
who knows,but are you good at chemistry, because I need help baddly
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