Posted by SDSU on Sunday, July 12, 2009 at 11:36pm.
Calculate the limit of the series
100[1 + 2*(2/3) + 2*(2/3)^2 + 2*(2/3)^3+...]
= 100 + 2[1 + 2/3 + (2/3)^2+ ...]
Make use of the relation:
1 + x + x^2 + .. = 1/(1-x)
(for x<1, which is the case here)
= 100 [1 + (4/3)[1 + 2/3 + (2/3)^2+ ...]
= 100 {1 + (4/3)[1/(1 - 2/3)]} = ?
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