Posted by **Amy** on Sunday, July 12, 2009 at 2:51pm.

The integral from 1 to 2 of x*the square root of (x-1) dx.

Using the substitution method, I said that u = x-1, du = 1 dx, and dx = du. I'm not sure how to plug u back into the equation since I still have that first x. Suggestions are greatly appreciated.

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