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September 23, 2014

September 23, 2014

Posted by **Amy** on Sunday, July 12, 2009 at 2:51pm.

Using the substitution method, I said that u = x-1, du = 1 dx, and dx = du. I'm not sure how to plug u back into the equation since I still have that first x. Suggestions are greatly appreciated.

- Calculus/Substitution -
**bobpursley**, Sunday, July 12, 2009 at 3:10pmLet u^2=x-1

2udu=dx

INT (u^2+1)u 2udu=

INT (2u^4+2U^2) du

revise your limits.

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