Calculus/Substitution
posted by Amy .
The integral from 1 to 2 of x*the square root of (x1) dx.
Using the substitution method, I said that u = x1, du = 1 dx, and dx = du. I'm not sure how to plug u back into the equation since I still have that first x. Suggestions are greatly appreciated.

Let u^2=x1
2udu=dx
INT (u^2+1)u 2udu=
INT (2u^4+2U^2) du
revise your limits.