Homework Help Forum: Calculus/Substitution

Posted by Amy on Sunday, July 12, 2009 at 2:51pm.

The integral from 1 to 2 of x*the square root of (x-1) dx. Using the substitution method, I said that u = x-1, du = 1 dx, and dx = du. I'm not sure how to plug u back into the equation since I still have that first x. Suggestions are greatly appreciated.

• Calculus/Substitution - bobpursley, Sunday, July 12, 2009 at 3:10pm

  Let u^2=x-1 2udu=dx INT (u^2+1)u 2udu= INT (2u^4+2U^2) du revise your limits.

  
  

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